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5x=(3x-6/5)
We move all terms to the left:
5x-((3x-6/5))=0
We add all the numbers together, and all the variables
5x-((+3x-6/5))=0
We multiply all the terms by the denominator
5x*5))-((+3x-6=0
We add all the numbers together, and all the variables
3x+5x*5))-((-6=0
Wy multiply elements
25x^2+3x-6=0
a = 25; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·25·(-6)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{609}}{2*25}=\frac{-3-\sqrt{609}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{609}}{2*25}=\frac{-3+\sqrt{609}}{50} $
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