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5x=1+6x^2
We move all terms to the left:
5x-(1+6x^2)=0
We get rid of parentheses
-6x^2+5x-1=0
a = -6; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·(-6)·(-1)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*-6}=\frac{-6}{-12} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*-6}=\frac{-4}{-12} =1/3 $
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