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5x=11-2(2x+1)
We move all terms to the left:
5x-(11-2(2x+1))=0
We calculate terms in parentheses: -(11-2(2x+1)), so:We get rid of parentheses
11-2(2x+1)
determiningTheFunctionDomain -2(2x+1)+11
We multiply parentheses
-4x-2+11
We add all the numbers together, and all the variables
-4x+9
Back to the equation:
-(-4x+9)
5x+4x-9=0
We add all the numbers together, and all the variables
9x-9=0
We move all terms containing x to the left, all other terms to the right
9x=9
x=9/9
x=1
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