5x=19-12/x

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Solution for 5x=19-12/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x = 19-(12/x) // - 19-(12/x)

5*x+12/x-19 = 0

5*x^1+12*x^-1-19*x^0 = 0

(5*x^2-19*x^1+12*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-19*x^1+12*x^0) = 0

x^1

5*x^2-19*x+12 = 0

5*x^2-19*x+12 = 0

DELTA = (-19)^2-(4*5*12)

DELTA = 121

DELTA > 0

x = (121^(1/2)+19)/(2*5) or x = (19-121^(1/2))/(2*5)

x = 3 or x = 4/5

x in { 4/5, 3}

x in { 4/5, 3 }

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