5x=2/3x+2

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Solution for 5x=2/3x+2 equation:



5x=2/3x+2
We move all terms to the left:
5x-(2/3x+2)=0
Domain of the equation: 3x+2)!=0
x∈R
We get rid of parentheses
5x-2/3x-2=0
We multiply all the terms by the denominator
5x*3x-2*3x-2=0
Wy multiply elements
15x^2-6x-2=0
a = 15; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·15·(-2)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{39}}{2*15}=\frac{6-2\sqrt{39}}{30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{39}}{2*15}=\frac{6+2\sqrt{39}}{30} $

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