5x=27+(x/5)

Solution for 5x=27+(x/5) equation:

5x=27+(x/5)

We move all terms to the left:

5x-(27+(x/5))=0

We add all the numbers together, and all the variables

5x-(27+(+x/5))=0

We multiply all the terms by the denominator


5x*5))-(27+(+x=0

We add all the numbers together, and all the variables

x+5x*5))-(27+(=0

Wy multiply elements

25x^2+x=0

a = 25; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·25·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*25}=\frac{-2}{50}
=-1/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*25}=\frac{0}{50}
=0
$