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5x=3x*3x-3
We move all terms to the left:
5x-(3x*3x-3)=0
We get rid of parentheses
5x-3x*3x+3=0
Wy multiply elements
-9x^2+5x+3=0
a = -9; b = 5; c = +3;
Δ = b2-4ac
Δ = 52-4·(-9)·3
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{133}}{2*-9}=\frac{-5-\sqrt{133}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{133}}{2*-9}=\frac{-5+\sqrt{133}}{-18} $
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