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5y(2)=20-y
We move all terms to the left:
5y(2)-(20-y)=0
We add all the numbers together, and all the variables
5y2-(-1y+20)=0
We add all the numbers together, and all the variables
5y^2-(-1y+20)=0
We get rid of parentheses
5y^2+1y-20=0
We add all the numbers together, and all the variables
5y^2+y-20=0
a = 5; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·5·(-20)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{401}}{2*5}=\frac{-1-\sqrt{401}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{401}}{2*5}=\frac{-1+\sqrt{401}}{10} $
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