5y(2)=20-y

Solution for 5y(2)=20-y equation:

5y(2)=20-y

We move all terms to the left:

5y(2)-(20-y)=0

We add all the numbers together, and all the variables

5y2-(-1y+20)=0

We add all the numbers together, and all the variables

5y^2-(-1y+20)=0

We get rid of parentheses

5y^2+1y-20=0

We add all the numbers together, and all the variables

5y^2+y-20=0

a = 5; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·5·(-20)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{401}}{2*5}=\frac{-1-\sqrt{401}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{401}}{2*5}=\frac{-1+\sqrt{401}}{10}
$