5y(2y+4)=7y

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Solution for 5y(2y+4)=7y equation:



5y(2y+4)=7y
We move all terms to the left:
5y(2y+4)-(7y)=0
We add all the numbers together, and all the variables
-7y+5y(2y+4)=0
We multiply parentheses
10y^2-7y+20y=0
We add all the numbers together, and all the variables
10y^2+13y=0
a = 10; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·10·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*10}=\frac{-26}{20} =-1+3/10 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*10}=\frac{0}{20} =0 $

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