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5y(2y+7)=0
We multiply parentheses
10y^2+35y=0
a = 10; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·10·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*10}=\frac{-70}{20} =-3+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*10}=\frac{0}{20} =0 $
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