5y(2y-7)=63

Solution for 5y(2y-7)=63 equation:

5y(2y-7)=63

We move all terms to the left:

5y(2y-7)-(63)=0

We multiply parentheses

10y^2-35y-63=0

a = 10; b = -35; c = -63;
Δ = b2-4ac
Δ = -352-4·10·(-63)
Δ = 3745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{3745}}{2*10}=\frac{35-\sqrt{3745}}{20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{3745}}{2*10}=\frac{35+\sqrt{3745}}{20}
$