5y(3y-2)=0

Solution for 5y(3y-2)=0 equation:

5y(3y-2)=0

We multiply parentheses

15y^2-10y=0

a = 15; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·15·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*15}=\frac{0}{30}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*15}=\frac{20}{30}
=2/3
$