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5y(6-2y)=-(19-18y)
We move all terms to the left:
5y(6-2y)-(-(19-18y))=0
We add all the numbers together, and all the variables
5y(-2y+6)-(-(-18y+19))=0
We multiply parentheses
-10y^2+30y-(-(-18y+19))=0
We calculate terms in parentheses: -(-(-18y+19)), so:We get rid of parentheses
-(-18y+19)
We get rid of parentheses
18y-19
Back to the equation:
-(18y-19)
-10y^2+30y-18y+19=0
We add all the numbers together, and all the variables
-10y^2+12y+19=0
a = -10; b = 12; c = +19;
Δ = b2-4ac
Δ = 122-4·(-10)·19
Δ = 904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{904}=\sqrt{4*226}=\sqrt{4}*\sqrt{226}=2\sqrt{226}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{226}}{2*-10}=\frac{-12-2\sqrt{226}}{-20} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{226}}{2*-10}=\frac{-12+2\sqrt{226}}{-20} $
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