5y(y+2)+25=0

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Solution for 5y(y+2)+25=0 equation: 



5y(y+2)+25=0

We multiply parentheses

5y^2+10y+25=0

a = 5; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·5·25
Δ = -400
Delta is less than zero, so there is no solution for the equation

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