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5y(y-10)=-5
We move all terms to the left:
5y(y-10)-(-5)=0
We add all the numbers together, and all the variables
5y(y-10)+5=0
We multiply parentheses
5y^2-50y+5=0
a = 5; b = -50; c = +5;
Δ = b2-4ac
Δ = -502-4·5·5
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20\sqrt{6}}{2*5}=\frac{50-20\sqrt{6}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20\sqrt{6}}{2*5}=\frac{50+20\sqrt{6}}{10} $
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