5y+(2y-4)=31

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Solution for 5y+(2y-4)=31 equation: 



5y+(2y-4)=31

We move all terms to the left:

5y+(2y-4)-(31)=0

We get rid of parentheses

5y+2y-4-31=0

We add all the numbers together, and all the variables

7y-35=0

We move all terms containing y to the left, all other terms to the right

7y=35

y=35/7

y=5

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