5y+(3y-3)=6y+11

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Solution for 5y+(3y-3)=6y+11 equation: 



5y+(3y-3)=6y+11

We move all terms to the left:

5y+(3y-3)-(6y+11)=0

We get rid of parentheses

5y+3y-6y-3-11=0

We add all the numbers together, and all the variables

2y-14=0

We move all terms containing y to the left, all other terms to the right

2y=14

y=14/2

y=7

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