5y+(3y-4)-(2+2y)=

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Solution for 5y+(3y-4)-(2+2y)= equation:


Simplifying
5y + (3y + -4) + -1(2 + 2y) = 0

Reorder the terms:
5y + (-4 + 3y) + -1(2 + 2y) = 0

Remove parenthesis around (-4 + 3y)
5y + -4 + 3y + -1(2 + 2y) = 0
5y + -4 + 3y + (2 * -1 + 2y * -1) = 0
5y + -4 + 3y + (-2 + -2y) = 0

Reorder the terms:
-4 + -2 + 5y + 3y + -2y = 0

Combine like terms: -4 + -2 = -6
-6 + 5y + 3y + -2y = 0

Combine like terms: 5y + 3y = 8y
-6 + 8y + -2y = 0

Combine like terms: 8y + -2y = 6y
-6 + 6y = 0

Solving
-6 + 6y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 6y = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 6y = 0 + 6
6y = 0 + 6

Combine like terms: 0 + 6 = 6
6y = 6

Divide each side by '6'.
y = 1

Simplifying
y = 1

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