5y+2(3y-1)=6y-(y+2)

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Solution for 5y+2(3y-1)=6y-(y+2) equation: 



5y+2(3y-1)=6y-(y+2)

We move all terms to the left:

5y+2(3y-1)-(6y-(y+2))=0

We multiply parentheses

5y+6y-(6y-(y+2))-2=0



We calculate terms in parentheses: -(6y-(y+2)), so:

6y-(y+2)

We get rid of parentheses

6y-y-2

We add all the numbers together, and all the variables

5y-2

Back to the equation:

-(5y-2)



We add all the numbers together, and all the variables

11y-(5y-2)-2=0

We get rid of parentheses

11y-5y+2-2=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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