5y+2(3y-1)=y-(y-2)

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Solution for 5y+2(3y-1)=y-(y-2) equation: 



5y+2(3y-1)=y-(y-2)

We move all terms to the left:

5y+2(3y-1)-(y-(y-2))=0

We multiply parentheses

5y+6y-(y-(y-2))-2=0



We calculate terms in parentheses: -(y-(y-2)), so:

y-(y-2)

We get rid of parentheses

y-y+2

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

11y-4=0

We move all terms containing y to the left, all other terms to the right

11y=4

y=4/11

y=4/11

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