5y+2(3y-4)=80

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Solution for 5y+2(3y-4)=80 equation: 



5y+2(3y-4)=80

We move all terms to the left:

5y+2(3y-4)-(80)=0

We multiply parentheses

5y+6y-8-80=0

We add all the numbers together, and all the variables

11y-88=0

We move all terms containing y to the left, all other terms to the right

11y=88

y=88/11

y=8

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