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5y+2(3y-4)=80
We move all terms to the left:
5y+2(3y-4)-(80)=0
We multiply parentheses
5y+6y-8-80=0
We add all the numbers together, and all the variables
11y-88=0
We move all terms containing y to the left, all other terms to the right
11y=88
y=88/11
y=8
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