5y+2(y-3)=3(y+1)-2

Solution for 5y+2(y-3)=3(y+1)-2 equation:

Simplifying
5y + 2(y + -3) = 3(y + 1) + -2

Reorder the terms:
5y + 2(-3 + y) = 3(y + 1) + -2
5y + (-3 * 2 + y * 2) = 3(y + 1) + -2
5y + (-6 + 2y) = 3(y + 1) + -2

Reorder the terms:
-6 + 5y + 2y = 3(y + 1) + -2

Combine like terms: 5y + 2y = 7y
-6 + 7y = 3(y + 1) + -2

Reorder the terms:
-6 + 7y = 3(1 + y) + -2
-6 + 7y = (1 * 3 + y * 3) + -2
-6 + 7y = (3 + 3y) + -2

Reorder the terms:
-6 + 7y = 3 + -2 + 3y

Combine like terms: 3 + -2 = 1
-6 + 7y = 1 + 3y

Solving
-6 + 7y = 1 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-6 + 7y + -3y = 1 + 3y + -3y

Combine like terms: 7y + -3y = 4y
-6 + 4y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-6 + 4y = 1 + 0
-6 + 4y = 1

Add '6' to each side of the equation.
-6 + 6 + 4y = 1 + 6

Combine like terms: -6 + 6 = 0
0 + 4y = 1 + 6
4y = 1 + 6

Combine like terms: 1 + 6 = 7
4y = 7

Divide each side by '4'.
y = 1.75

Simplifying
y = 1.75