5y+2(y-6)=(y+1)-2

Solution for 5y+2(y-6)=(y+1)-2 equation:

5y+2(y-6)=(y+1)-2

We move all terms to the left:

5y+2(y-6)-((y+1)-2)=0

We multiply parentheses

5y+2y-((y+1)-2)-12=0


We calculate terms in parentheses: -((y+1)-2), so:

(y+1)-2

We get rid of parentheses

y+1-2

We add all the numbers together, and all the variables

y-1

Back to the equation:

-(y-1)


We add all the numbers together, and all the variables

7y-(y-1)-12=0

We get rid of parentheses

7y-y+1-12=0

We add all the numbers together, and all the variables

6y-11=0

We move all terms containing y to the left, all other terms to the right

6y=11

y=11/6

y=1+5/6