5y+2(y-8)=4(y+1)-3

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Solution for 5y+2(y-8)=4(y+1)-3 equation:


Simplifying
5y + 2(y + -8) = 4(y + 1) + -3

Reorder the terms:
5y + 2(-8 + y) = 4(y + 1) + -3
5y + (-8 * 2 + y * 2) = 4(y + 1) + -3
5y + (-16 + 2y) = 4(y + 1) + -3

Reorder the terms:
-16 + 5y + 2y = 4(y + 1) + -3

Combine like terms: 5y + 2y = 7y
-16 + 7y = 4(y + 1) + -3

Reorder the terms:
-16 + 7y = 4(1 + y) + -3
-16 + 7y = (1 * 4 + y * 4) + -3
-16 + 7y = (4 + 4y) + -3

Reorder the terms:
-16 + 7y = 4 + -3 + 4y

Combine like terms: 4 + -3 = 1
-16 + 7y = 1 + 4y

Solving
-16 + 7y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-16 + 7y + -4y = 1 + 4y + -4y

Combine like terms: 7y + -4y = 3y
-16 + 3y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
-16 + 3y = 1 + 0
-16 + 3y = 1

Add '16' to each side of the equation.
-16 + 16 + 3y = 1 + 16

Combine like terms: -16 + 16 = 0
0 + 3y = 1 + 16
3y = 1 + 16

Combine like terms: 1 + 16 = 17
3y = 17

Divide each side by '3'.
y = 5.666666667

Simplifying
y = 5.666666667

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