5y+2(y-8)=4(y-2)-5

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Solution for 5y+2(y-8)=4(y-2)-5 equation: 


Simplifying
5y + 2(y + -8) = 4(y + -2) + -5

Reorder the terms:
5y + 2(-8 + y) = 4(y + -2) + -5
5y + (-8 * 2 + y * 2) = 4(y + -2) + -5
5y + (-16 + 2y) = 4(y + -2) + -5

Reorder the terms:
-16 + 5y + 2y = 4(y + -2) + -5

Combine like terms: 5y + 2y = 7y
-16 + 7y = 4(y + -2) + -5

Reorder the terms:
-16 + 7y = 4(-2 + y) + -5
-16 + 7y = (-2 * 4 + y * 4) + -5
-16 + 7y = (-8 + 4y) + -5

Reorder the terms:
-16 + 7y = -8 + -5 + 4y

Combine like terms: -8 + -5 = -13
-16 + 7y = -13 + 4y

Solving
-16 + 7y = -13 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-16 + 7y + -4y = -13 + 4y + -4y

Combine like terms: 7y + -4y = 3y
-16 + 3y = -13 + 4y + -4y

Combine like terms: 4y + -4y = 0
-16 + 3y = -13 + 0
-16 + 3y = -13

Add '16' to each side of the equation.
-16 + 16 + 3y = -13 + 16

Combine like terms: -16 + 16 = 0
0 + 3y = -13 + 16
3y = -13 + 16

Combine like terms: -13 + 16 = 3
3y = 3

Divide each side by '3'.
y = 1

Simplifying
y = 1

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