5y+2-4(-3y-1)=3(y-4)

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Solution for 5y+2-4(-3y-1)=3(y-4) equation: 



5y+2-4(-3y-1)=3(y-4)

We move all terms to the left:

5y+2-4(-3y-1)-(3(y-4))=0

We multiply parentheses

5y+12y-(3(y-4))+4+2=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We add all the numbers together, and all the variables

17y-(3y-12)+6=0

We get rid of parentheses

17y-3y+12+6=0

We add all the numbers together, and all the variables

14y+18=0

We move all terms containing y to the left, all other terms to the right

14y=-18

y=-18/14

y=-1+2/7

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