5y+2=(1/2)10y+4

Solution for 5y+2=(1/2)10y+4 equation:

5y+2=(1/2)10y+4

We move all terms to the left:

5y+2-((1/2)10y+4)=0


Domain of the equation: 2)10y+4)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

5y-((+1/2)10y+4)+2=0

We multiply all the terms by the denominator


5y*2)10y+4)-((+2*2)10y+4)+1=0

We add all the numbers together, and all the variables

5y*2)10y+4)-(410y+4)+1=0

Wy multiply elements

10y^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{20}=0$