If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5y+2=1/3(10y+4)
We move all terms to the left:
5y+2-(1/3(10y+4))=0
Domain of the equation: 3(10y+4))!=0We multiply all the terms by the denominator
y∈R
5y*3(10y+4))-(1+2*3(10y+4))=0
Wy multiply elements
15y^2(1+6y(1=0
| 40+3.5m=57.5 | | 8/x=2/18 | | -3(2j+5)+4(3j-2)=15 | | |b-15|=13 | | 7y+2(1y-5)+1y=40 | | 18=n+32 | | -4x+5-13+39=180 | | 5u+5(-u)=u+8 | | -4x+5=-13+39=180 | | 2(d-3)+3d=29 | | x=4+46 | | (x/4)+8=17 | | (3x-3)°=(x+19)° | | 85=6w | | (X+4/2)+(x+6/5)=6 | | -0.4=0.9x=-2.29 | | 95=x5 | | X+4/2+x+6/5=6 | | x2-32=112 | | 35=r/5 | | 0.6=0.95^m | | 5xX8=0 | | 35=r5 | | 72+x1=62 | | -n+2(7-4n)=8(1-2n)+8n | | 1/2(10x+4)=-12 | | 0.5t=0.9+0.6t | | 5-(8v+5)=-4(1+3v) | | 6(x+2)+8=56 | | 15-3w=-30 | | 1/20(4p-6)=1/10(p+8) | | 6+3e=e+8 |