5y+3(y-4)=4(y+1)-3

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Solution for 5y+3(y-4)=4(y+1)-3 equation:


Simplifying
5y + 3(y + -4) = 4(y + 1) + -3

Reorder the terms:
5y + 3(-4 + y) = 4(y + 1) + -3
5y + (-4 * 3 + y * 3) = 4(y + 1) + -3
5y + (-12 + 3y) = 4(y + 1) + -3

Reorder the terms:
-12 + 5y + 3y = 4(y + 1) + -3

Combine like terms: 5y + 3y = 8y
-12 + 8y = 4(y + 1) + -3

Reorder the terms:
-12 + 8y = 4(1 + y) + -3
-12 + 8y = (1 * 4 + y * 4) + -3
-12 + 8y = (4 + 4y) + -3

Reorder the terms:
-12 + 8y = 4 + -3 + 4y

Combine like terms: 4 + -3 = 1
-12 + 8y = 1 + 4y

Solving
-12 + 8y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-12 + 8y + -4y = 1 + 4y + -4y

Combine like terms: 8y + -4y = 4y
-12 + 4y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
-12 + 4y = 1 + 0
-12 + 4y = 1

Add '12' to each side of the equation.
-12 + 12 + 4y = 1 + 12

Combine like terms: -12 + 12 = 0
0 + 4y = 1 + 12
4y = 1 + 12

Combine like terms: 1 + 12 = 13
4y = 13

Divide each side by '4'.
y = 3.25

Simplifying
y = 3.25

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