5y+3(y-4)=8y-2(y-10)

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Solution for 5y+3(y-4)=8y-2(y-10) equation:


Simplifying
5y + 3(y + -4) = 8y + -2(y + -10)

Reorder the terms:
5y + 3(-4 + y) = 8y + -2(y + -10)
5y + (-4 * 3 + y * 3) = 8y + -2(y + -10)
5y + (-12 + 3y) = 8y + -2(y + -10)

Reorder the terms:
-12 + 5y + 3y = 8y + -2(y + -10)

Combine like terms: 5y + 3y = 8y
-12 + 8y = 8y + -2(y + -10)

Reorder the terms:
-12 + 8y = 8y + -2(-10 + y)
-12 + 8y = 8y + (-10 * -2 + y * -2)
-12 + 8y = 8y + (20 + -2y)

Reorder the terms:
-12 + 8y = 20 + 8y + -2y

Combine like terms: 8y + -2y = 6y
-12 + 8y = 20 + 6y

Solving
-12 + 8y = 20 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-12 + 8y + -6y = 20 + 6y + -6y

Combine like terms: 8y + -6y = 2y
-12 + 2y = 20 + 6y + -6y

Combine like terms: 6y + -6y = 0
-12 + 2y = 20 + 0
-12 + 2y = 20

Add '12' to each side of the equation.
-12 + 12 + 2y = 20 + 12

Combine like terms: -12 + 12 = 0
0 + 2y = 20 + 12
2y = 20 + 12

Combine like terms: 20 + 12 = 32
2y = 32

Divide each side by '2'.
y = 16

Simplifying
y = 16

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