5y+3(y-6)=69y+1)-3

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Solution for 5y+3(y-6)=69y+1)-3 equation: 



5y+3(y-6)=69y+1)-3

We move all terms to the left:

5y+3(y-6)-(69y+1)-3)=0

We add all the numbers together, and all the variables

5y+3(y-6)-(69y+1)=0

We multiply parentheses

5y+3y-(69y+1)-18=0

We get rid of parentheses

5y+3y-69y-1-18=0

We add all the numbers together, and all the variables

-61y-19=0

We move all terms containing y to the left, all other terms to the right

-61y=19

y=19/-61

y=-19/61

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