5y+3(y-6)=69y+1)-3

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Solution for 5y+3(y-6)=69y+1)-3 equation:



5y+3(y-6)=69y+1)-3
We move all terms to the left:
5y+3(y-6)-(69y+1)-3)=0
We add all the numbers together, and all the variables
5y+3(y-6)-(69y+1)=0
We multiply parentheses
5y+3y-(69y+1)-18=0
We get rid of parentheses
5y+3y-69y-1-18=0
We add all the numbers together, and all the variables
-61y-19=0
We move all terms containing y to the left, all other terms to the right
-61y=19
y=19/-61
y=-19/61

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