5y+3(y-9)=6(y+1)-2

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Solution for 5y+3(y-9)=6(y+1)-2 equation: 



5y+3(y-9)=6(y+1)-2

We move all terms to the left:

5y+3(y-9)-(6(y+1)-2)=0

We multiply parentheses

5y+3y-(6(y+1)-2)-27=0



We calculate terms in parentheses: -(6(y+1)-2), so:

6(y+1)-2

We multiply parentheses

6y+6-2

We add all the numbers together, and all the variables

6y+4

Back to the equation:

-(6y+4)



We add all the numbers together, and all the variables

8y-(6y+4)-27=0

We get rid of parentheses

8y-6y-4-27=0

We add all the numbers together, and all the variables

2y-31=0

We move all terms containing y to the left, all other terms to the right

2y=31

y=31/2

y=15+1/2

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