5y+3+2y+4=7(y+1)

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Solution for 5y+3+2y+4=7(y+1) equation:


Simplifying
5y + 3 + 2y + 4 = 7(y + 1)

Reorder the terms:
3 + 4 + 5y + 2y = 7(y + 1)

Combine like terms: 3 + 4 = 7
7 + 5y + 2y = 7(y + 1)

Combine like terms: 5y + 2y = 7y
7 + 7y = 7(y + 1)

Reorder the terms:
7 + 7y = 7(1 + y)
7 + 7y = (1 * 7 + y * 7)
7 + 7y = (7 + 7y)

Add '-7' to each side of the equation.
7 + -7 + 7y = 7 + -7 + 7y

Combine like terms: 7 + -7 = 0
0 + 7y = 7 + -7 + 7y
7y = 7 + -7 + 7y

Combine like terms: 7 + -7 = 0
7y = 0 + 7y
7y = 7y

Add '-7y' to each side of the equation.
7y + -7y = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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