5y+3-2(-3y-3)=3(y-3)

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Solution for 5y+3-2(-3y-3)=3(y-3) equation: 



5y+3-2(-3y-3)=3(y-3)

We move all terms to the left:

5y+3-2(-3y-3)-(3(y-3))=0

We multiply parentheses

5y+6y-(3(y-3))+6+3=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

11y-(3y-9)+9=0

We get rid of parentheses

11y-3y+9+9=0

We add all the numbers together, and all the variables

8y+18=0

We move all terms containing y to the left, all other terms to the right

8y=-18

y=-18/8

y=-2+1/4

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