5y+3-3(-5y-1)=4(y-1)

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Solution for 5y+3-3(-5y-1)=4(y-1) equation: 



5y+3-3(-5y-1)=4(y-1)

We move all terms to the left:

5y+3-3(-5y-1)-(4(y-1))=0

We multiply parentheses

5y+15y-(4(y-1))+3+3=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

20y-(4y-4)+6=0

We get rid of parentheses

20y-4y+4+6=0

We add all the numbers together, and all the variables

16y+10=0

We move all terms containing y to the left, all other terms to the right

16y=-10

y=-10/16

y=-5/8

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