5y+38=-7(y-2)

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Solution for 5y+38=-7(y-2) equation: 



5y+38=-7(y-2)

We move all terms to the left:

5y+38-(-7(y-2))=0



We calculate terms in parentheses: -(-7(y-2)), so:

-7(y-2)

We multiply parentheses

-7y+14

Back to the equation:

-(-7y+14)



We get rid of parentheses

5y+7y-14+38=0

We add all the numbers together, and all the variables

12y+24=0

We move all terms containing y to the left, all other terms to the right

12y=-24

y=-24/12

y=-2

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