5y+3=7(y-1)

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Solution for 5y+3=7(y-1) equation: 



5y+3=7(y-1)

We move all terms to the left:

5y+3-(7(y-1))=0



We calculate terms in parentheses: -(7(y-1)), so:

7(y-1)

We multiply parentheses

7y-7

Back to the equation:

-(7y-7)



We get rid of parentheses

5y-7y+7+3=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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