5y+4/4y+5=2

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Solution for 5y+4/4y+5=2 equation: 



5y+4/4y+5=2

We move all terms to the left:

5y+4/4y+5-(2)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We add all the numbers together, and all the variables

5y+4/4y+3=0

We multiply all the terms by the denominator


5y*4y+3*4y+4=0

Wy multiply elements

20y^2+12y+4=0

a = 20; b = 12; c = +4;
Δ = b2-4ac
Δ = 122-4·20·4
Δ = -176
Delta is less than zero, so there is no solution for the equation

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