5y+6(4y+5)=9(3y+3)+8

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Solution for 5y+6(4y+5)=9(3y+3)+8 equation: 



5y+6(4y+5)=9(3y+3)+8

We move all terms to the left:

5y+6(4y+5)-(9(3y+3)+8)=0

We multiply parentheses

5y+24y-(9(3y+3)+8)+30=0



We calculate terms in parentheses: -(9(3y+3)+8), so:

9(3y+3)+8

We multiply parentheses

27y+27+8

We add all the numbers together, and all the variables

27y+35

Back to the equation:

-(27y+35)



We add all the numbers together, and all the variables

29y-(27y+35)+30=0

We get rid of parentheses

29y-27y-35+30=0

We add all the numbers together, and all the variables

2y-5=0

We move all terms containing y to the left, all other terms to the right

2y=5

y=5/2

y=2+1/2

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