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5y+7=6+2(y+2)
We move all terms to the left:
5y+7-(6+2(y+2))=0
We calculate terms in parentheses: -(6+2(y+2)), so:We get rid of parentheses
6+2(y+2)
determiningTheFunctionDomain 2(y+2)+6
We multiply parentheses
2y+4+6
We add all the numbers together, and all the variables
2y+10
Back to the equation:
-(2y+10)
5y-2y-10+7=0
We add all the numbers together, and all the variables
3y-3=0
We move all terms containing y to the left, all other terms to the right
3y=3
y=3/3
y=1
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