5y-(-(2-3y)+4)=-9y-(-(2+4y)-8)

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Solution for 5y-(-(2-3y)+4)=-9y-(-(2+4y)-8) equation: 



5y--(2-3y)+4=-9y--(2+4y)-8

We move all terms to the left:

5y--(2-3y)+4-(-9y--(2+4y)-8)=0

We add all the numbers together, and all the variables

5y-(-3y+2)-(-9y--(4y+2)-8)+4-=0

We add all the numbers together, and all the variables

5y-(-3y+2)-(-9y--(4y+2)-8)=0

We use the square of the difference formula

5y-(-3y+2)-(-9y+(4y+2)-8)=0

We get rid of parentheses

5y+3y-(-9y+(4y+2)-8)-2=0



We calculate terms in parentheses: -(-9y+(4y+2)-8), so:

-9y+(4y+2)-8

We get rid of parentheses

-9y+4y+2-8

We add all the numbers together, and all the variables

-5y-6

Back to the equation:

-(-5y-6)



We add all the numbers together, and all the variables

8y-(-5y-6)-2=0

We get rid of parentheses

8y+5y+6-2=0

We add all the numbers together, and all the variables

13y+4=0

We move all terms containing y to the left, all other terms to the right

13y=-4

y=-4/13

y=-4/13

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