5y-(2y+3)=4(y-4)

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Solution for 5y-(2y+3)=4(y-4) equation:


Simplifying
5y + -1(2y + 3) = 4(y + -4)

Reorder the terms:
5y + -1(3 + 2y) = 4(y + -4)
5y + (3 * -1 + 2y * -1) = 4(y + -4)
5y + (-3 + -2y) = 4(y + -4)

Reorder the terms:
-3 + 5y + -2y = 4(y + -4)

Combine like terms: 5y + -2y = 3y
-3 + 3y = 4(y + -4)

Reorder the terms:
-3 + 3y = 4(-4 + y)
-3 + 3y = (-4 * 4 + y * 4)
-3 + 3y = (-16 + 4y)

Solving
-3 + 3y = -16 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-3 + 3y + -4y = -16 + 4y + -4y

Combine like terms: 3y + -4y = -1y
-3 + -1y = -16 + 4y + -4y

Combine like terms: 4y + -4y = 0
-3 + -1y = -16 + 0
-3 + -1y = -16

Add '3' to each side of the equation.
-3 + 3 + -1y = -16 + 3

Combine like terms: -3 + 3 = 0
0 + -1y = -16 + 3
-1y = -16 + 3

Combine like terms: -16 + 3 = -13
-1y = -13

Divide each side by '-1'.
y = 13

Simplifying
y = 13

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