5y-(2y+5)=-(2y+15)+y

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Solution for 5y-(2y+5)=-(2y+15)+y equation: 



5y-(2y+5)=-(2y+15)+y

We move all terms to the left:

5y-(2y+5)-(-(2y+15)+y)=0

We get rid of parentheses

5y-2y-(-(2y+15)+y)-5=0



We calculate terms in parentheses: -(-(2y+15)+y), so:

-(2y+15)+y

We add all the numbers together, and all the variables

y-(2y+15)

We get rid of parentheses

y-2y-15

We add all the numbers together, and all the variables

-1y-15

Back to the equation:

-(-1y-15)



We add all the numbers together, and all the variables

3y-(-1y-15)-5=0

We get rid of parentheses

3y+1y+15-5=0

We add all the numbers together, and all the variables

4y+10=0

We move all terms containing y to the left, all other terms to the right

4y=-10

y=-10/4

y=-2+1/2

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