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5y-(3y+7)=9+2(y-8)
We move all terms to the left:
5y-(3y+7)-(9+2(y-8))=0
We get rid of parentheses
5y-3y-(9+2(y-8))-7=0
We calculate terms in parentheses: -(9+2(y-8)), so:We add all the numbers together, and all the variables
9+2(y-8)
determiningTheFunctionDomain 2(y-8)+9
We multiply parentheses
2y-16+9
We add all the numbers together, and all the variables
2y-7
Back to the equation:
-(2y-7)
2y-(2y-7)-7=0
We get rid of parentheses
2y-2y+7-7=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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