5y-(3y-2)+6=2(y+4)

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Solution for 5y-(3y-2)+6=2(y+4) equation: 


Simplifying
5y + -1(3y + -2) + 6 = 2(y + 4)

Reorder the terms:
5y + -1(-2 + 3y) + 6 = 2(y + 4)
5y + (-2 * -1 + 3y * -1) + 6 = 2(y + 4)
5y + (2 + -3y) + 6 = 2(y + 4)

Reorder the terms:
2 + 6 + 5y + -3y = 2(y + 4)

Combine like terms: 2 + 6 = 8
8 + 5y + -3y = 2(y + 4)

Combine like terms: 5y + -3y = 2y
8 + 2y = 2(y + 4)

Reorder the terms:
8 + 2y = 2(4 + y)
8 + 2y = (4 * 2 + y * 2)
8 + 2y = (8 + 2y)

Add '-8' to each side of the equation.
8 + -8 + 2y = 8 + -8 + 2y

Combine like terms: 8 + -8 = 0
0 + 2y = 8 + -8 + 2y
2y = 8 + -8 + 2y

Combine like terms: 8 + -8 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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