5y-(5(2+y)=3y)-5-0

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Solution for 5y-(5(2+y)=3y)-5-0 equation: 



5y-(5(2+y)=3y)-5-0

We move all terms to the left:

5y-(5(2+y)-(3y)-5-0)=0

We add all the numbers together, and all the variables

5y-(5(y+2)-3y-5-0)=0



We calculate terms in parentheses: -(5(y+2)-3y-5-0), so:

5(y+2)-3y-5-0

We add all the numbers together, and all the variables

-3y+5(y+2)-5

We multiply parentheses

-3y+5y+10-5

We add all the numbers together, and all the variables

2y+5

Back to the equation:

-(2y+5)



We get rid of parentheses

5y-2y-5=0

We add all the numbers together, and all the variables

3y-5=0

We move all terms containing y to the left, all other terms to the right

3y=5

y=5/3

y=1+2/3

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