5y-1+y+39=7y+40-3y

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Solution for 5y-1+y+39=7y+40-3y equation: 



5y-1+y+39=7y+40-3y

We move all terms to the left:

5y-1+y+39-(7y+40-3y)=0

We add all the numbers together, and all the variables

5y+y-(4y+40)-1+39=0

We add all the numbers together, and all the variables

6y-(4y+40)+38=0

We get rid of parentheses

6y-4y-40+38=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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