5y-1+y+42=8y+50-5y

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Solution for 5y-1+y+42=8y+50-5y equation: 



5y-1+y+42=8y+50-5y

We move all terms to the left:

5y-1+y+42-(8y+50-5y)=0

We add all the numbers together, and all the variables

5y+y-(3y+50)-1+42=0

We add all the numbers together, and all the variables

6y-(3y+50)+41=0

We get rid of parentheses

6y-3y-50+41=0

We add all the numbers together, and all the variables

3y-9=0

We move all terms containing y to the left, all other terms to the right

3y=9

y=9/3

y=3

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