5y-1/2=-2/y-2

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Solution for 5y-1/2=-2/y-2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5*y-(1/2) = -2/y-2 // + -2/y-2

5*y-(-2/y)-(1/2)+2 = 0

5*y+2*y^-1-1/2+2 = 0

5*y^1+2*y^-1+3/2*y^0 = 0

(5*y^2+3/2*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(5*y^2+3/2*y^1+2*y^0) = 0

y^1

5*y^2+(3/2)*y+2 = 0

5*y^2+(3/2)*y+2 = 0

DELTA = (3/2)^2-(2*4*5)

DELTA = -151/4

DELTA < 0

y in { } 

y belongs to the empty set

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