5y-10+2(3y-4)=26

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Solution for 5y-10+2(3y-4)=26 equation: 



5y-10+2(3y-4)=26

We move all terms to the left:

5y-10+2(3y-4)-(26)=0

We add all the numbers together, and all the variables

5y+2(3y-4)-36=0

We multiply parentheses

5y+6y-8-36=0

We add all the numbers together, and all the variables

11y-44=0

We move all terms containing y to the left, all other terms to the right

11y=44

y=44/11

y=4

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